Solve {-2*[-5*(14-5-2)-3*(-7)+6]+22-6}*(+3)=

$$\{ - 2 \cdot [ - 5 \cdot ( 14 - 5 - 2 ) - 3 \cdot ( - 7 ) + 6 ] + 22 - 6 \} \cdot ( + 3 ) =$$

Evaluate

$$96$$

Solution Steps

Subtract 5 from 14 to get 9.

$$\left(-2\left(-5\left(9-2\right)-3\left(-7\right)+6\right)+22-6\right)\times 3$$

Subtract 2 from 9 to get 7.

$$\left(-2\left(-5\times 7-3\left(-7\right)+6\right)+22-6\right)\times 3$$

Multiply -5 and 7 to get -35.

$$\left(-2\left(-35-3\left(-7\right)+6\right)+22-6\right)\times 3$$

Multiply 3 and -7 to get -21.

$$\left(-2\left(-35-\left(-21\right)+6\right)+22-6\right)\times 3$$

The opposite of -21 is 21.

$$\left(-2\left(-35+21+6\right)+22-6\right)\times 3$$

Add -35 and 21 to get -14.

$$\left(-2\left(-14+6\right)+22-6\right)\times 3$$

Add -14 and 6 to get -8.

$$\left(-2\left(-8\right)+22-6\right)\times 3$$

Multiply -2 and -8 to get 16.

$$\left(16+22-6\right)\times 3$$

Add 16 and 22 to get 38.

$$\left(38-6\right)\times 3$$

Subtract 6 from 38 to get 32.

$$32\times 3$$

Multiply 32 and 3 to get 96.

$$96$$

Factor

$$2^{5}\times 3$$