Solve {-18-[-27-(19-10-(-2))+(-7*4+15)]}-31

$$\{ - 18 - [ - 27 - ( 19 - 10 - ( - 2 ) ) + ( - 7 \cdot 4 + 15 ) ] \} - 31$$

Evaluate

$$2$$

Solution Steps

Subtract 10 from 19 to get 9.

$$-18-\left(-27-\left(9-\left(-2\right)\right)-7\times 4+15\right)-31$$

The opposite of -2 is 2.

$$-18-\left(-27-\left(9+2\right)-7\times 4+15\right)-31$$

Add 9 and 2 to get 11.

$$-18-\left(-27-11-7\times 4+15\right)-31$$

Subtract 11 from -27 to get -38.

$$-18-\left(-38-7\times 4+15\right)-31$$

Multiply -7 and 4 to get -28.

$$-18-\left(-38-28+15\right)-31$$

Subtract 28 from -38 to get -66.

$$-18-\left(-66+15\right)-31$$

Add -66 and 15 to get -51.

$$-18-\left(-51\right)-31$$

The opposite of -51 is 51.

$$-18+51-31$$

Add -18 and 51 to get 33.

$$33-31$$

Subtract 31 from 33 to get 2.

$$2$$

Factor

$$2$$