Solve {(34+16)+[5-46*2-6^0]+48-sqrt{324}}

$$\{ ( 34 + 16 ) + [ 5 - 46 \times 2 - 6 ^ { 0 } ] + 48 - \sqrt { 324 } \}$$

Evaluate

$$-8$$

Solution Steps

Add 34 and 16 to get 50.

$$50+5-46\times 2-6^{0}+48-\sqrt{324}$$

Multiply 46 and 2 to get 92.

$$50+5-92-6^{0}+48-\sqrt{324}$$

Subtract 92 from 5 to get -87.

$$50+-87-6^{0}+48-\sqrt{324}$$

Calculate 6 to the power of 0 and get 1.

$$50-87-1+48-\sqrt{324}$$

Subtract 1 from -87 to get -88.

$$50-88+48-\sqrt{324}$$

Subtract 88 from 50 to get -38.

$$-38+48-\sqrt{324}$$

Add -38 and 48 to get 10.

$$10-\sqrt{324}$$

Calculate the square root of 324 and get 18.

$$10-18$$

Subtract 18 from 10 to get -8.

$$-8$$

Factor

$$-8$$