Solve {(-4^2)+(-2)^2}div(-3)^2

$$\{ ( - 4 ^ { 2 } ) + ( - 2 ) ^ { 2 } \} \div ( - 3 ) ^ { 2 }$$

Evaluate

$$-\frac{4}{3}\approx -1.333333333$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$\frac{-16+\left(-2\right)^{2}}{\left(-3\right)^{2}}$$

Calculate -2 to the power of 2 and get 4.

$$\frac{-16+4}{\left(-3\right)^{2}}$$

Add -16 and 4 to get -12.

$$\frac{-12}{\left(-3\right)^{2}}$$

Calculate -3 to the power of 2 and get 9.

$$\frac{-12}{9}$$

Reduce the fraction \frac{-12}{9} to lowest terms by extracting and canceling out 3.

$$-\frac{4}{3}$$

Factor

$$-\frac{4}{3} = -1\frac{1}{3} = -1.3333333333333333$$