Solve {(-3)*[(-3)^2-5]-(6-10)}:(-2)-|10-(-2)^4|

$$\{ ( - 3 ) \cdot [ ( - 3 ) ^ { 2 } - 5 ] - ( 6 - 10 ) \} : ( - 2 ) - | 10 - ( - 2 ) ^ { 4 } |$$

Evaluate

$$-2$$

Solution Steps

Calculate -3 to the power of 2 and get 9.

$$\frac{-3\left(9-5\right)-\left(6-10\right)}{-2}-|10-\left(-2\right)^{4}|$$

Subtract 5 from 9 to get 4.

$$\frac{-3\times 4-\left(6-10\right)}{-2}-|10-\left(-2\right)^{4}|$$

Multiply -3 and 4 to get -12.

$$\frac{-12-\left(6-10\right)}{-2}-|10-\left(-2\right)^{4}|$$

Subtract 10 from 6 to get -4.

$$\frac{-12-\left(-4\right)}{-2}-|10-\left(-2\right)^{4}|$$

The opposite of -4 is 4.

$$\frac{-12+4}{-2}-|10-\left(-2\right)^{4}|$$

Add -12 and 4 to get -8.

$$\frac{-8}{-2}-|10-\left(-2\right)^{4}|$$

Divide -8 by -2 to get 4.

$$4-|10-\left(-2\right)^{4}|$$

Calculate -2 to the power of 4 and get 16.

$$4-|10-16|$$

Subtract 16 from 10 to get -6.

$$4-|-6|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -6 is 6.

$$4-6$$

Subtract 6 from 4 to get -2.

$$-2$$

Factor

$$-2$$