Solve {x-2/4+3y+1/3+7/6=0

$$\{ \frac { x - 2 } { 4 } + \frac { 3 y + 1 } { 3 } + \frac { 7 } { 6 } = 0$$

Solve for x

$$x=-4y-4$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 12, the least common multiple of 4,3,6.

$$3\left(x-2\right)+4\left(3y+1\right)+14=0$$

Use the distributive property to multiply 3 by x-2.

$$3x-6+4\left(3y+1\right)+14=0$$

Use the distributive property to multiply 4 by 3y+1.

$$3x-6+12y+4+14=0$$

Add -6 and 4 to get -2.

$$3x-2+12y+14=0$$

Add -2 and 14 to get 12.

$$3x+12+12y=0$$

Subtract 12 from both sides. Anything subtracted from zero gives its negation.

$$3x+12y=-12$$

Subtract 12y from both sides.

$$3x=-12-12y$$

The equation is in standard form.

$$3x=-12y-12$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{-12y-12}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{-12y-12}{3}$$

Divide -12-12y by 3.

$$x=-4y-4$$