Solve {[6*(5+1)-2*3]:(2+3)}-{[(4*8-2):6]-2}

$$\{ [ 6 \cdot ( 5 + 1 ) - 2 \cdot 3 ] : ( 2 + 3 ) \} - \{ [ ( 4 \cdot 8 - 2 ) : 6 ] - 2 \}$$

Evaluate

$$3$$

Solution Steps

Add 5 and 1 to get 6.

$$\frac{6\times 6-2\times 3}{2+3}-\left(\frac{4\times 8-2}{6}-2\right)$$

Multiply 6 and 6 to get 36.

$$\frac{36-2\times 3}{2+3}-\left(\frac{4\times 8-2}{6}-2\right)$$

Multiply 2 and 3 to get 6.

$$\frac{36-6}{2+3}-\left(\frac{4\times 8-2}{6}-2\right)$$

Subtract 6 from 36 to get 30.

$$\frac{30}{2+3}-\left(\frac{4\times 8-2}{6}-2\right)$$

Add 2 and 3 to get 5.

$$\frac{30}{5}-\left(\frac{4\times 8-2}{6}-2\right)$$

Divide 30 by 5 to get 6.

$$6-\left(\frac{4\times 8-2}{6}-2\right)$$

Multiply 4 and 8 to get 32.

$$6-\left(\frac{32-2}{6}-2\right)$$

Subtract 2 from 32 to get 30.

$$6-\left(\frac{30}{6}-2\right)$$

Divide 30 by 6 to get 5.

$$6-\left(5-2\right)$$

Subtract 2 from 5 to get 3.

$$6-3$$

Subtract 3 from 6 to get 3.

$$3$$

Factor

$$3$$