Solve {[1-5+(6+7-4+1)*(-8+10-15)]+(-10):(-2)}:(-25-8)=

$$\{ [ 1 - 5 + ( 6 + 7 - 4 + 1 ) \cdot ( - 8 + 10 - 15 ) ] + ( - 10 ) : ( - 2 ) \} : ( - 25 - 8 ) =$$

Evaluate

$$\frac{43}{11}\approx 3.909090909$$

Solution Steps

Subtract 5 from 1 to get -4.

$$\frac{-4+\left(6+7-4+1\right)\left(-8+10-15\right)+\frac{-10}{-2}}{-25-8}$$

Add 6 and 7 to get 13.

$$\frac{-4+\left(13-4+1\right)\left(-8+10-15\right)+\frac{-10}{-2}}{-25-8}$$

Subtract 4 from 13 to get 9.

$$\frac{-4+\left(9+1\right)\left(-8+10-15\right)+\frac{-10}{-2}}{-25-8}$$

Add 9 and 1 to get 10.

$$\frac{-4+10\left(-8+10-15\right)+\frac{-10}{-2}}{-25-8}$$

Add -8 and 10 to get 2.

$$\frac{-4+10\left(2-15\right)+\frac{-10}{-2}}{-25-8}$$

Subtract 15 from 2 to get -13.

$$\frac{-4+10\left(-13\right)+\frac{-10}{-2}}{-25-8}$$

Multiply 10 and -13 to get -130.

$$\frac{-4-130+\frac{-10}{-2}}{-25-8}$$

Subtract 130 from -4 to get -134.

$$\frac{-134+\frac{-10}{-2}}{-25-8}$$

Divide -10 by -2 to get 5.

$$\frac{-134+5}{-25-8}$$

Add -134 and 5 to get -129.

$$\frac{-129}{-25-8}$$

Subtract 8 from -25 to get -33.

$$\frac{-129}{-33}$$

Reduce the fraction \frac{-129}{-33} to lowest terms by extracting and canceling out -3.

$$\frac{43}{11}$$

Factor

$$\frac{43}{11} = 3\frac{10}{11} = 3.909090909090909$$