Solve {[(8*4+3)div7+(3+15+5)*3]*2-(19-7)+6}*2+1

$$\{ [ ( 8 \cdot 4 + 3 ) \div 7 + ( 3 + 15 + 5 ) \cdot 3 ] \cdot 2 - ( 19 - 7 ) + 6 \} \cdot 2 + 1$$

Evaluate

$$285$$

Solution Steps

Multiply 8 and 4 to get 32.

$$\left(\left(\frac{32+3}{7}+\left(3+15+5\right)\times 3\right)\times 2-\left(19-7\right)+6\right)\times 2+1$$

Add 32 and 3 to get 35.

$$\left(\left(\frac{35}{7}+\left(3+15+5\right)\times 3\right)\times 2-\left(19-7\right)+6\right)\times 2+1$$

Divide 35 by 7 to get 5.

$$\left(\left(5+\left(3+15+5\right)\times 3\right)\times 2-\left(19-7\right)+6\right)\times 2+1$$

Add 3 and 15 to get 18.

$$\left(\left(5+\left(18+5\right)\times 3\right)\times 2-\left(19-7\right)+6\right)\times 2+1$$

Add 18 and 5 to get 23.

$$\left(\left(5+23\times 3\right)\times 2-\left(19-7\right)+6\right)\times 2+1$$

Multiply 23 and 3 to get 69.

$$\left(\left(5+69\right)\times 2-\left(19-7\right)+6\right)\times 2+1$$

Add 5 and 69 to get 74.

$$\left(74\times 2-\left(19-7\right)+6\right)\times 2+1$$

Multiply 74 and 2 to get 148.

$$\left(148-\left(19-7\right)+6\right)\times 2+1$$

Subtract 7 from 19 to get 12.

$$\left(148-12+6\right)\times 2+1$$

Subtract 12 from 148 to get 136.

$$\left(136+6\right)\times 2+1$$

Add 136 and 6 to get 142.

$$142\times 2+1$$

Multiply 142 and 2 to get 284.

$$284+1$$

Add 284 and 1 to get 285.

$$285$$

Factor

$$3\times 5\times 19$$