Solve {[(4^2-1^2)-(3^2-2^2)]:(-5)}

$$\{ [ ( 4 ^ { 2 } - 1 ^ { 2 } ) - ( 3 ^ { 2 } - 2 ^ { 2 } ) ] : ( - 5 ) \}$$

Evaluate

$$-2$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$\frac{16-1^{2}-\left(3^{2}-2^{2}\right)}{-5}$$

Calculate 1 to the power of 2 and get 1.

$$\frac{16-1-\left(3^{2}-2^{2}\right)}{-5}$$

Subtract 1 from 16 to get 15.

$$\frac{15-\left(3^{2}-2^{2}\right)}{-5}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{15-\left(9-2^{2}\right)}{-5}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{15-\left(9-4\right)}{-5}$$

Subtract 4 from 9 to get 5.

$$\frac{15-5}{-5}$$

Subtract 5 from 15 to get 10.

$$\frac{10}{-5}$$

Divide 10 by -5 to get -2.

$$-2$$

Factor

$$-2$$