Solve {[(30)(2)+40]-[(-12+30)+(-20+6)]div12}=

$$\{ [ ( 30 ) ( 2 ) + 40 ] - [ ( - 12 + 30 ) + ( - 20 + 6 ) ] \div 12 \} =$$

Evaluate

$$\frac{299}{3}\approx 99.666666667$$

Solution Steps

Multiply 30 and 2 to get 60.

$$60+40-\frac{-12+30-20+6}{12}$$

Add 60 and 40 to get 100.

$$100-\frac{-12+30-20+6}{12}$$

Add -12 and 30 to get 18.

$$100-\frac{18-20+6}{12}$$

Subtract 20 from 18 to get -2.

$$100-\frac{-2+6}{12}$$

Add -2 and 6 to get 4.

$$100-\frac{4}{12}$$

Reduce the fraction \frac{4}{12} to lowest terms by extracting and canceling out 4.

$$100-\frac{1}{3}$$

Convert 100 to fraction \frac{300}{3}.

$$\frac{300}{3}-\frac{1}{3}$$

Since \frac{300}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{300-1}{3}$$

Subtract 1 from 300 to get 299.

$$\frac{299}{3}$$

Factor

$$\frac{13 \cdot 23}{3} = 99\frac{2}{3} = 99.66666666666667$$