Solve {[9/7+(4-53):704*(5+34*28)]*30}

$$\{ [ \frac { 9 } { 7 } + ( 4 - 53 ) : 704 \cdot ( 5 + 34 \cdot 28 ) ] \cdot 30 \}$$

Evaluate

$$-\frac{438975}{224}\approx -1959.709821429$$

Solution Steps

Subtract 53 from 4 to get -49.

$$\left(\frac{9}{7}+\frac{-49}{704}\left(5+34\times 28\right)\right)\times 30$$

Fraction \frac{-49}{704} can be rewritten as -\frac{49}{704} by extracting the negative sign.

$$\left(\frac{9}{7}-\frac{49}{704}\left(5+34\times 28\right)\right)\times 30$$

Multiply 34 and 28 to get 952.

$$\left(\frac{9}{7}-\frac{49}{704}\left(5+952\right)\right)\times 30$$

Add 5 and 952 to get 957.

$$\left(\frac{9}{7}-\frac{49}{704}\times 957\right)\times 30$$

Express -\frac{49}{704}\times 957 as a single fraction.

$$\left(\frac{9}{7}+\frac{-49\times 957}{704}\right)\times 30$$

Multiply -49 and 957 to get -46893.

$$\left(\frac{9}{7}+\frac{-46893}{704}\right)\times 30$$

Reduce the fraction \frac{-46893}{704} to lowest terms by extracting and canceling out 11.

$$\left(\frac{9}{7}-\frac{4263}{64}\right)\times 30$$

Least common multiple of 7 and 64 is 448. Convert \frac{9}{7} and \frac{4263}{64} to fractions with denominator 448.

$$\left(\frac{576}{448}-\frac{29841}{448}\right)\times 30$$

Since \frac{576}{448} and \frac{29841}{448} have the same denominator, subtract them by subtracting their numerators.

$$\frac{576-29841}{448}\times 30$$

Subtract 29841 from 576 to get -29265.

$$-\frac{29265}{448}\times 30$$

Express -\frac{29265}{448}\times 30 as a single fraction.

$$\frac{-29265\times 30}{448}$$

Multiply -29265 and 30 to get -877950.

$$\frac{-877950}{448}$$

Reduce the fraction \frac{-877950}{448} to lowest terms by extracting and canceling out 2.

$$-\frac{438975}{224}$$

Factor

$$-\frac{438975}{224} = -1959\frac{159}{224} = -1959.7098214285713$$