Solve {[5/4-(-2+3/4)^2]:(5/4)^2-(-2)^3}:[43/5-(-frac{4}{5})^2*(2-frac{3}{4})]

$$\{ [ \frac { 5 } { 4 } - ( - 2 + \frac { 3 } { 4 } ) ^ { 2 } ] : ( \frac { 5 } { 4 } ) ^ { 2 } - ( - 2 ) ^ { 3 } \} : [ \frac { 43 } { 5 } - ( - \frac { 4 } { 5 } ) ^ { 2 } \cdot ( 2 - \frac { 3 } { 4 } ) ]$$

Evaluate

$$1$$

Solution Steps

Add -2 and \frac{3}{4} to get -\frac{5}{4}.

$$\frac{\frac{\frac{5}{4}-\left(-\frac{5}{4}\right)^{2}}{\left(\frac{5}{4}\right)^{2}}-\left(-2\right)^{3}}{\frac{43}{5}-\left(-\frac{4}{5}\right)^{2}\left(2-\frac{3}{4}\right)}$$

Calculate -\frac{5}{4} to the power of 2 and get \frac{25}{16}.

$$\frac{\frac{\frac{5}{4}-\frac{25}{16}}{\left(\frac{5}{4}\right)^{2}}-\left(-2\right)^{3}}{\frac{43}{5}-\left(-\frac{4}{5}\right)^{2}\left(2-\frac{3}{4}\right)}$$

Subtract \frac{25}{16} from \frac{5}{4} to get -\frac{5}{16}.

$$\frac{\frac{-\frac{5}{16}}{\left(\frac{5}{4}\right)^{2}}-\left(-2\right)^{3}}{\frac{43}{5}-\left(-\frac{4}{5}\right)^{2}\left(2-\frac{3}{4}\right)}$$

Calculate \frac{5}{4} to the power of 2 and get \frac{25}{16}.

$$\frac{\frac{-\frac{5}{16}}{\frac{25}{16}}-\left(-2\right)^{3}}{\frac{43}{5}-\left(-\frac{4}{5}\right)^{2}\left(2-\frac{3}{4}\right)}$$

Divide -\frac{5}{16} by \frac{25}{16} by multiplying -\frac{5}{16} by the reciprocal of \frac{25}{16}.

$$\frac{-\frac{5}{16}\times \frac{16}{25}-\left(-2\right)^{3}}{\frac{43}{5}-\left(-\frac{4}{5}\right)^{2}\left(2-\frac{3}{4}\right)}$$

Multiply -\frac{5}{16} and \frac{16}{25} to get -\frac{1}{5}.

$$\frac{-\frac{1}{5}-\left(-2\right)^{3}}{\frac{43}{5}-\left(-\frac{4}{5}\right)^{2}\left(2-\frac{3}{4}\right)}$$

Calculate -2 to the power of 3 and get -8.

$$\frac{-\frac{1}{5}-\left(-8\right)}{\frac{43}{5}-\left(-\frac{4}{5}\right)^{2}\left(2-\frac{3}{4}\right)}$$

The opposite of -8 is 8.

$$\frac{-\frac{1}{5}+8}{\frac{43}{5}-\left(-\frac{4}{5}\right)^{2}\left(2-\frac{3}{4}\right)}$$

Add -\frac{1}{5} and 8 to get \frac{39}{5}.

$$\frac{\frac{39}{5}}{\frac{43}{5}-\left(-\frac{4}{5}\right)^{2}\left(2-\frac{3}{4}\right)}$$

Calculate -\frac{4}{5} to the power of 2 and get \frac{16}{25}.

$$\frac{\frac{39}{5}}{\frac{43}{5}-\frac{16}{25}\left(2-\frac{3}{4}\right)}$$

Subtract \frac{3}{4} from 2 to get \frac{5}{4}.

$$\frac{\frac{39}{5}}{\frac{43}{5}-\frac{16}{25}\times \frac{5}{4}}$$

Multiply \frac{16}{25} and \frac{5}{4} to get \frac{4}{5}.

$$\frac{\frac{39}{5}}{\frac{43}{5}-\frac{4}{5}}$$

Subtract \frac{4}{5} from \frac{43}{5} to get \frac{39}{5}.

$$\frac{\frac{39}{5}}{\frac{39}{5}}$$

Divide \frac{39}{5} by \frac{39}{5} to get 1.

$$1$$

Factor

$$1$$