Solve [c:4+a+0]:6+d=

$$[ c : 4 + a + 0 ] : 6 + d =$$

Evaluate

$$\frac{a}{6}+\frac{c}{24}+d$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply a+0 times \frac{4}{4}.

$$\frac{\frac{c}{4}+\frac{4\left(a+0\right)}{4}}{6}+d$$

Since \frac{c}{4} and \frac{4\left(a+0\right)}{4} have the same denominator, add them by adding their numerators.

$$\frac{\frac{c+4\left(a+0\right)}{4}}{6}+d$$

Do the multiplications in c+4\left(a+0\right).

$$\frac{\frac{c+4a}{4}}{6}+d$$

Express \frac{\frac{c+4a}{4}}{6} as a single fraction.

$$\frac{c+4a}{4\times 6}+d$$

Multiply 4 and 6 to get 24.

$$\frac{c+4a}{24}+d$$

To add or subtract expressions, expand them to make their denominators the same. Multiply d times \frac{24}{24}.

$$\frac{c+4a}{24}+\frac{24d}{24}$$

Since \frac{c+4a}{24} and \frac{24d}{24} have the same denominator, add them by adding their numerators.

$$\frac{c+4a+24d}{24}$$

Expand

$$\frac{a}{6}+\frac{c}{24}+d$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply a+0 times \frac{4}{4}.

$$\frac{\frac{c}{4}+\frac{4\left(a+0\right)}{4}}{6}+d$$

Since \frac{c}{4} and \frac{4\left(a+0\right)}{4} have the same denominator, add them by adding their numerators.

$$\frac{\frac{c+4\left(a+0\right)}{4}}{6}+d$$

Do the multiplications in c+4\left(a+0\right).

$$\frac{\frac{c+4a}{4}}{6}+d$$

Express \frac{\frac{c+4a}{4}}{6} as a single fraction.

$$\frac{c+4a}{4\times 6}+d$$

Multiply 4 and 6 to get 24.

$$\frac{c+4a}{24}+d$$

To add or subtract expressions, expand them to make their denominators the same. Multiply d times \frac{24}{24}.

$$\frac{c+4a}{24}+\frac{24d}{24}$$

Since \frac{c+4a}{24} and \frac{24d}{24} have the same denominator, add them by adding their numerators.

$$\frac{c+4a+24d}{24}$$