Solve [8-(6-4)]:3+(24-8):(16-12)-18:(9-3)=3

$$[ 8 - ( 6 - 4 ) ] : 3 + ( 24 - 8 ) : ( 16 - 12 ) - 18 : ( 9 - 3 ) = 3$$

Verify

Solution Steps

Multiply both sides of the equation by 3.

$$8-\left(6-4\right)+\frac{3}{4}\left(24-8\right)-\frac{1}{2}\times 18=9$$

Subtract 4 from 6 to get 2.

$$8-2+\frac{3}{4}\left(24-8\right)-\frac{1}{2}\times 18=9$$

Subtract 2 from 8 to get 6.

$$6+\frac{3}{4}\left(24-8\right)-\frac{1}{2}\times 18=9$$

Subtract 8 from 24 to get 16.

$$6+\frac{3}{4}\times 16-\frac{1}{2}\times 18=9$$

Express \frac{3}{4}\times 16 as a single fraction.

$$6+\frac{3\times 16}{4}-\frac{1}{2}\times 18=9$$

Multiply 3 and 16 to get 48.

$$6+\frac{48}{4}-\frac{1}{2}\times 18=9$$

Divide 48 by 4 to get 12.

$$6+12-\frac{1}{2}\times 18=9$$

Add 6 and 12 to get 18.

$$18-\frac{1}{2}\times 18=9$$

Express -\frac{1}{2}\times 18 as a single fraction.

$$18+\frac{-18}{2}=9$$

Divide -18 by 2 to get -9.

$$18-9=9$$

Subtract 9 from 18 to get 9.

$$9=9$$

Compare 9 and 9.

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