Solve [6^2-5+(2^3+2-2*3)+12*5]:19}^2-[(3*7-2^4):5]*2

$$[ 6 ^ { 2 } - 5 + ( 2 ^ { 3 } + 2 - 2 \times 3 ) + 12 \times 5 ] : 19 \} ^ { 2 } - [ ( 3 \times 7 - 2 ^ { 4 } ) : 5 ] \times 2$$

Evaluate

$$5$$

Solution Steps

Calculate 6 to the power of 2 and get 36.

$$\frac{36-5+2^{3}+2-2\times 3+12\times 5}{19}$$

Subtract 5 from 36 to get 31.

$$\frac{31+2^{3}+2-2\times 3+12\times 5}{19}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{31+8+2-2\times 3+12\times 5}{19}$$

Add 8 and 2 to get 10.

$$\frac{31+10-2\times 3+12\times 5}{19}$$

Multiply 2 and 3 to get 6.

$$\frac{31+10-6+12\times 5}{19}$$

Subtract 6 from 10 to get 4.

$$\frac{31+4+12\times 5}{19}$$

Add 31 and 4 to get 35.

$$\frac{35+12\times 5}{19}$$

Multiply 12 and 5 to get 60.

$$\frac{35+60}{19}$$

Add 35 and 60 to get 95.

$$\frac{95}{19}$$

Divide 95 by 19 to get 5.

$$5$$

Factor

$$5$$