Solve [520*(286*1/10-20)]^2-(3333+4321+111)

$$[ 520 \times ( 286 \times \frac { 1 } { 10 } - 20 ) ] ^ { 2 } - ( 3333 + 4321 + 111 )$$

Evaluate

$$19991019$$

Solution Steps

Multiply 286 and \frac{1}{10} to get \frac{143}{5}.

$$\left(520\left(\frac{143}{5}-20\right)\right)^{2}-\left(3333+4321+111\right)$$

Subtract 20 from \frac{143}{5} to get \frac{43}{5}.

$$\left(520\times \frac{43}{5}\right)^{2}-\left(3333+4321+111\right)$$

Multiply 520 and \frac{43}{5} to get 4472.

$$4472^{2}-\left(3333+4321+111\right)$$

Calculate 4472 to the power of 2 and get 19998784.

$$19998784-\left(3333+4321+111\right)$$

Add 3333 and 4321 to get 7654.

$$19998784-\left(7654+111\right)$$

Add 7654 and 111 to get 7765.

$$19998784-7765$$

Subtract 7765 from 19998784 to get 19991019.

$$19991019$$

Factor

$$3\times 6663673$$