Solve [5(4+2*3)-(7-2)^2]div[9^2-8^1*7]

$$[ 5 ( 4 + 2 \cdot 3 ) - ( 7 - 2 ) ^ { 2 } ] \div [ 9 ^ { 2 } - 8 ^ { 1 } \cdot 7 ]$$

Evaluate

$$1$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\frac{5\left(4+6\right)-\left(7-2\right)^{2}}{9^{2}-8^{1}\times 7}$$

Add 4 and 6 to get 10.

$$\frac{5\times 10-\left(7-2\right)^{2}}{9^{2}-8^{1}\times 7}$$

Multiply 5 and 10 to get 50.

$$\frac{50-\left(7-2\right)^{2}}{9^{2}-8^{1}\times 7}$$

Subtract 2 from 7 to get 5.

$$\frac{50-5^{2}}{9^{2}-8^{1}\times 7}$$

Calculate 5 to the power of 2 and get 25.

$$\frac{50-25}{9^{2}-8^{1}\times 7}$$

Subtract 25 from 50 to get 25.

$$\frac{25}{9^{2}-8^{1}\times 7}$$

Calculate 9 to the power of 2 and get 81.

$$\frac{25}{81-8^{1}\times 7}$$

Calculate 8 to the power of 1 and get 8.

$$\frac{25}{81-8\times 7}$$

Multiply 8 and 7 to get 56.

$$\frac{25}{81-56}$$

Subtract 56 from 81 to get 25.

$$\frac{25}{25}$$

Divide 25 by 25 to get 1.

$$1$$

Factor

$$1$$