Solve [5^2*3/15+2*(9-3)^2]-8*4+7*3=

$$[ 5 ^ { 2 } \times 3 / 15 + 2 \times ( 9 - 3 ) ^ { 2 } ] - 8 \times 4 + 7 \times 3 =$$

Evaluate

$$66$$

Solution Steps

Calculate 5 to the power of 2 and get 25.

$$25\times \frac{3}{15}+2\left(9-3\right)^{2}-8\times 4+7\times 3$$

Reduce the fraction \frac{3}{15} to lowest terms by extracting and canceling out 3.

$$25\times \frac{1}{5}+2\left(9-3\right)^{2}-8\times 4+7\times 3$$

Multiply 25 and \frac{1}{5} to get 5.

$$5+2\left(9-3\right)^{2}-8\times 4+7\times 3$$

Subtract 3 from 9 to get 6.

$$5+2\times 6^{2}-8\times 4+7\times 3$$

Calculate 6 to the power of 2 and get 36.

$$5+2\times 36-8\times 4+7\times 3$$

Multiply 2 and 36 to get 72.

$$5+72-8\times 4+7\times 3$$

Add 5 and 72 to get 77.

$$77-8\times 4+7\times 3$$

Multiply 8 and 4 to get 32.

$$77-32+7\times 3$$

Subtract 32 from 77 to get 45.

$$45+7\times 3$$

Multiply 7 and 3 to get 21.

$$45+21$$

Add 45 and 21 to get 66.

$$66$$

Factor

$$2\times 3\times 11$$