Solve [5^2*3/15+2*(9-3)^2]-8

$$[ 5 ^ { 2 } \times 3 / 15 + 2 \times ( 9 - 3 ) ^ { 2 } ] - 8$$

Evaluate

$$69$$

Solution Steps

Calculate 5 to the power of 2 and get 25.

$$25\times \frac{3}{15}+2\left(9-3\right)^{2}-8$$

Reduce the fraction \frac{3}{15} to lowest terms by extracting and canceling out 3.

$$25\times \frac{1}{5}+2\left(9-3\right)^{2}-8$$

Multiply 25 and \frac{1}{5} to get 5.

$$5+2\left(9-3\right)^{2}-8$$

Subtract 3 from 9 to get 6.

$$5+2\times 6^{2}-8$$

Calculate 6 to the power of 2 and get 36.

$$5+2\times 36-8$$

Multiply 2 and 36 to get 72.

$$5+72-8$$

Add 5 and 72 to get 77.

$$77-8$$

Subtract 8 from 77 to get 69.

$$69$$

Factor

$$3\times 23$$