Solve [4000^2+[182(2618)]^2]^1/2

$$[ 4000 ^ { 2 } + [ 182 ( 2618 ) ] ^ { 2 } ] ^ { 1 / 2 }$$

Evaluate

$$4\sqrt{14190336161}\approx 476492.789636947$$

Solution Steps

Calculate 4000 to the power of 2 and get 16000000.

$$\left(16000000+\left(182\times 2618\right)^{2}\right)^{\frac{1}{2}}$$

Multiply 182 and 2618 to get 476476.

$$\left(16000000+476476^{2}\right)^{\frac{1}{2}}$$

Calculate 476476 to the power of 2 and get 227029378576.

$$\left(16000000+227029378576\right)^{\frac{1}{2}}$$

Add 16000000 and 227029378576 to get 227045378576.

$$227045378576^{\frac{1}{2}}$$