Solve [4-(2/3-1/4)]*2/3

$$[ 4 - ( \frac { 2 } { 3 } - \frac { 1 } { 4 } ) ] \times \frac { 2 } { 3 }$$

Evaluate

$$\frac{43}{18}\approx 2.388888889$$

Solution Steps

Least common multiple of 3 and 4 is 12. Convert \frac{2}{3} and \frac{1}{4} to fractions with denominator 12.

$$\left(4-\left(\frac{8}{12}-\frac{3}{12}\right)\right)\times \frac{2}{3}$$

Since \frac{8}{12} and \frac{3}{12} have the same denominator, subtract them by subtracting their numerators.

$$\left(4-\frac{8-3}{12}\right)\times \frac{2}{3}$$

Subtract 3 from 8 to get 5.

$$\left(4-\frac{5}{12}\right)\times \frac{2}{3}$$

Convert 4 to fraction \frac{48}{12}.

$$\left(\frac{48}{12}-\frac{5}{12}\right)\times \frac{2}{3}$$

Since \frac{48}{12} and \frac{5}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{48-5}{12}\times \frac{2}{3}$$

Subtract 5 from 48 to get 43.

$$\frac{43}{12}\times \frac{2}{3}$$

Multiply \frac{43}{12} times \frac{2}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{43\times 2}{12\times 3}$$

Do the multiplications in the fraction \frac{43\times 2}{12\times 3}.

$$\frac{86}{36}$$

Reduce the fraction \frac{86}{36} to lowest terms by extracting and canceling out 2.

$$\frac{43}{18}$$

Factor

$$\frac{43}{2 \cdot 3 ^ {2}} = 2\frac{7}{18} = 2.388888888888889$$