Solve [4*(3/4-3/8)]*4/29

$$[ 4 \times ( \frac { 3 } { 4 } - \frac { 3 } { 8 } ) ] \times \frac { 4 } { 29 }$$

Evaluate

$$\frac{6}{29}\approx 0.206896552$$

Solution Steps

Least common multiple of 4 and 8 is 8. Convert \frac{3}{4} and \frac{3}{8} to fractions with denominator 8.

$$4\left(\frac{6}{8}-\frac{3}{8}\right)\times \frac{4}{29}$$

Since \frac{6}{8} and \frac{3}{8} have the same denominator, subtract them by subtracting their numerators.

$$4\times \frac{6-3}{8}\times \frac{4}{29}$$

Subtract 3 from 6 to get 3.

$$4\times \frac{3}{8}\times \frac{4}{29}$$

Express 4\times \frac{3}{8} as a single fraction.

$$\frac{4\times 3}{8}\times \frac{4}{29}$$

Multiply 4 and 3 to get 12.

$$\frac{12}{8}\times \frac{4}{29}$$

Reduce the fraction \frac{12}{8} to lowest terms by extracting and canceling out 4.

$$\frac{3}{2}\times \frac{4}{29}$$

Multiply \frac{3}{2} times \frac{4}{29} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 4}{2\times 29}$$

Do the multiplications in the fraction \frac{3\times 4}{2\times 29}.

$$\frac{12}{58}$$

Reduce the fraction \frac{12}{58} to lowest terms by extracting and canceling out 2.

$$\frac{6}{29}$$

Factor

$$\frac{2 \cdot 3}{29} = 0.20689655172413793$$