Solve [3x-18]+[10x(10)]+12

$$[ 3 x - 18 ] + [ 10 x ( 10 ) ] + 12$$

Evaluate

$$103x-6$$

Solution Steps

Multiply 10 and 10 to get 100.

$$3x-18+100x+12$$

Combine 3x and 100x to get 103x.

$$103x-18+12$$

Add -18 and 12 to get -6.

$$103x-6$$

Differentiate w.r.t. x

$$103$$

Steps Using Derivative Rule for Sum

Multiply 10 and 10 to get 100.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x-18+100x+12)$$

Combine 3x and 100x to get 103x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(103x-18+12)$$

Add -18 and 12 to get -6.

$$\frac{\mathrm{d}}{\mathrm{d}x}(103x-6)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$103x^{1-1}$$

Subtract 1 from 1.

$$103x^{0}$$

For any term t except 0, t^{0}=1.

$$103\times 1$$

For any term t, t\times 1=t and 1t=t.

$$103$$