Solve [3-{8-(-3)}]div[4{12+(-3)*6}]

$$[ 3 - \{ 8 - ( - 3 ) \} ] \div [ 4 \{ 12 + ( - 3 ) \times 6 \} ]$$

Evaluate

$$\frac{1}{3}\approx 0.333333333$$

Solution Steps

The opposite of -3 is 3.

$$\frac{3-\left(8+3\right)}{4\left(12-3\times 6\right)}$$

Add 8 and 3 to get 11.

$$\frac{3-11}{4\left(12-3\times 6\right)}$$

Subtract 11 from 3 to get -8.

$$\frac{-8}{4\left(12-3\times 6\right)}$$

Multiply -3 and 6 to get -18.

$$\frac{-8}{4\left(12-18\right)}$$

Subtract 18 from 12 to get -6.

$$\frac{-8}{4\left(-6\right)}$$

Multiply 4 and -6 to get -24.

$$\frac{-8}{-24}$$

Reduce the fraction \frac{-8}{-24} to lowest terms by extracting and canceling out -8.

$$\frac{1}{3}$$

Factor

$$\frac{1}{3} = 0.3333333333333333$$