Solve [3*(7-2*4)+4:(1-3)]:[(2-7)*(4-7):(-3)]

$$[ 3 \cdot ( 7 - 2 \cdot 4 ) + 4 : ( 1 - 3 ) ] : [ ( 2 - 7 ) \cdot ( 4 - 7 ) : ( - 3 ) ]$$

Evaluate

$$1$$

Solution Steps

Multiply 2 and 4 to get 8.

$$\frac{3\left(7-8\right)+\frac{4}{1-3}}{\frac{\left(2-7\right)\left(4-7\right)}{-3}}$$

Subtract 8 from 7 to get -1.

$$\frac{3\left(-1\right)+\frac{4}{1-3}}{\frac{\left(2-7\right)\left(4-7\right)}{-3}}$$

Multiply 3 and -1 to get -3.

$$\frac{-3+\frac{4}{1-3}}{\frac{\left(2-7\right)\left(4-7\right)}{-3}}$$

Subtract 3 from 1 to get -2.

$$\frac{-3+\frac{4}{-2}}{\frac{\left(2-7\right)\left(4-7\right)}{-3}}$$

Divide 4 by -2 to get -2.

$$\frac{-3-2}{\frac{\left(2-7\right)\left(4-7\right)}{-3}}$$

Subtract 2 from -3 to get -5.

$$\frac{-5}{\frac{\left(2-7\right)\left(4-7\right)}{-3}}$$

Subtract 7 from 2 to get -5.

$$\frac{-5}{\frac{-5\left(4-7\right)}{-3}}$$

Subtract 7 from 4 to get -3.

$$\frac{-5}{\frac{-5\left(-3\right)}{-3}}$$

Multiply -5 and -3 to get 15.

$$\frac{-5}{\frac{15}{-3}}$$

Divide 15 by -3 to get -5.

$$\frac{-5}{-5}$$

Divide -5 by -5 to get 1.

$$1$$

Factor

$$1$$