Solve [3^4:3^-2]^3*3^-3=

$$[ 3 ^ { 4 } : 3 ^ { - 2 } ] ^ { 3 } \cdot 3 ^ { - 3 } =$$

Evaluate

$$14348907$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract -2 from 4 to get 6.

$$\left(3^{6}\right)^{3}\times 3^{-3}$$

To raise a power to another power, multiply the exponents. Multiply 6 and 3 to get 18.

$$3^{18}\times 3^{-3}$$

To multiply powers of the same base, add their exponents. Add 18 and -3 to get 15.

$$3^{15}$$

Calculate 3 to the power of 15 and get 14348907.

$$14348907$$

Factor

$$3^{15}$$