Solve [3^3*2^2-4*(27-23)/2]+(12/4)^2=109

$$[ 3 ^ { 3 } \cdot 2 ^ { 2 } - 4 \cdot \frac { ( 27 - 23 ) } { 2 } ] + ( \frac { 12 } { 4 } ) ^ { 2 } = 109$$

Verify

Solution Steps

Multiply both sides of the equation by 2.

$$2\left(3^{3}\times 2^{2}-4\times \frac{27-23}{2}\right)+2\times \left(\frac{12}{4}\right)^{2}=218$$

Calculate 3 to the power of 3 and get 27.

$$2\left(27\times 2^{2}-4\times \frac{27-23}{2}\right)+2\times \left(\frac{12}{4}\right)^{2}=218$$

Calculate 2 to the power of 2 and get 4.

$$2\left(27\times 4-4\times \frac{27-23}{2}\right)+2\times \left(\frac{12}{4}\right)^{2}=218$$

Multiply 27 and 4 to get 108.

$$2\left(108-4\times \frac{27-23}{2}\right)+2\times \left(\frac{12}{4}\right)^{2}=218$$

Subtract 23 from 27 to get 4.

$$2\left(108-4\times \frac{4}{2}\right)+2\times \left(\frac{12}{4}\right)^{2}=218$$

Divide 4 by 2 to get 2.

$$2\left(108-4\times 2\right)+2\times \left(\frac{12}{4}\right)^{2}=218$$

Multiply 4 and 2 to get 8.

$$2\left(108-8\right)+2\times \left(\frac{12}{4}\right)^{2}=218$$

Subtract 8 from 108 to get 100.

$$2\times 100+2\times \left(\frac{12}{4}\right)^{2}=218$$

Multiply 2 and 100 to get 200.

$$200+2\times \left(\frac{12}{4}\right)^{2}=218$$

Divide 12 by 4 to get 3.

$$200+2\times 3^{2}=218$$

Calculate 3 to the power of 2 and get 9.

$$200+2\times 9=218$$

Multiply 2 and 9 to get 18.

$$200+18=218$$

Add 200 and 18 to get 218.

$$218=218$$

Compare 218 and 218.

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