Solve [3^2-2*(-5)+(-2)*6]^2=

$$[ 3 ^ { 2 } - 2 \cdot ( - 5 ) + ( - 2 ) \cdot 6 ] ^ { 2 } =$$

Evaluate

$$49$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$\left(9-2\left(-5\right)-2\times 6\right)^{2}$$

Multiply 2 and -5 to get -10.

$$\left(9-\left(-10\right)-2\times 6\right)^{2}$$

The opposite of -10 is 10.

$$\left(9+10-2\times 6\right)^{2}$$

Add 9 and 10 to get 19.

$$\left(19-2\times 6\right)^{2}$$

Multiply -2 and 6 to get -12.

$$\left(19-12\right)^{2}$$

Subtract 12 from 19 to get 7.

$$7^{2}$$

Calculate 7 to the power of 2 and get 49.

$$49$$

Factor

$$7^{2}$$