Solve [266-200(1-x)]*115geq9200

$$[ 266 - 200 ( 1 - x ) ] \times 115 \geq 9200$$

Solve for x

$$x\geq \frac{7}{100}$$

Solution Steps

Divide both sides by 115. Since 115 is positive, the inequality direction remains the same.

$$266-200\left(1-x\right)\geq \frac{9200}{115}$$

Divide 9200 by 115 to get 80.

$$266-200\left(1-x\right)\geq 80$$

Use the distributive property to multiply -200 by 1-x.

$$266-200+200x\geq 80$$

Subtract 200 from 266 to get 66.

$$66+200x\geq 80$$

Subtract 66 from both sides.

$$200x\geq 80-66$$

Subtract 66 from 80 to get 14.

$$200x\geq 14$$

Divide both sides by 200. Since 200 is positive, the inequality direction remains the same.

$$x\geq \frac{14}{200}$$

Reduce the fraction \frac{14}{200} to lowest terms by extracting and canceling out 2.

$$x\geq \frac{7}{100}$$