Solve [2y(a^2-6a^2)+(y+3y)*a^2]:(3a^2)

$$[ 2 y ( a ^ { 2 } - 6 a ^ { 2 } ) + ( y + 3 y ) \cdot a ^ { 2 } ] : ( 3 a ^ { 2 } )$$

Evaluate

$$-2y$$

Solution Steps

Combine a^{2} and -6a^{2} to get -5a^{2}.

$$\frac{2y\left(-5\right)a^{2}+\left(y+3y\right)a^{2}}{3a^{2}}$$

Multiply 2 and -5 to get -10.

$$\frac{-10ya^{2}+\left(y+3y\right)a^{2}}{3a^{2}}$$

Combine y and 3y to get 4y.

$$\frac{-10ya^{2}+4ya^{2}}{3a^{2}}$$

Combine -10ya^{2} and 4ya^{2} to get -6ya^{2}.

$$\frac{-6ya^{2}}{3a^{2}}$$

Cancel out 3a^{2} in both numerator and denominator.

$$-2y$$

Expand

$$-2y$$

Solution Steps

Combine a^{2} and -6a^{2} to get -5a^{2}.

$$\frac{2y\left(-5\right)a^{2}+\left(y+3y\right)a^{2}}{3a^{2}}$$

Multiply 2 and -5 to get -10.

$$\frac{-10ya^{2}+\left(y+3y\right)a^{2}}{3a^{2}}$$

Combine y and 3y to get 4y.

$$\frac{-10ya^{2}+4ya^{2}}{3a^{2}}$$

Combine -10ya^{2} and 4ya^{2} to get -6ya^{2}.

$$\frac{-6ya^{2}}{3a^{2}}$$

Cancel out 3a^{2} in both numerator and denominator.

$$-2y$$