Solve [2-(3+2)*(-1)]+6*[8-(3-4)*2]=

$$[ 2 - ( 3 + 2 ) \cdot ( - 1 ) ] + 6 \cdot [ 8 - ( 3 - 4 ) \cdot 2 ] =$$

Evaluate

$$67$$

Solution Steps

Add 3 and 2 to get 5.

$$2-5\left(-1\right)+6\left(8-\left(3-4\right)\times 2\right)$$

Multiply 5 and -1 to get -5.

$$2-\left(-5\right)+6\left(8-\left(3-4\right)\times 2\right)$$

The opposite of -5 is 5.

$$2+5+6\left(8-\left(3-4\right)\times 2\right)$$

Add 2 and 5 to get 7.

$$7+6\left(8-\left(3-4\right)\times 2\right)$$

Subtract 4 from 3 to get -1.

$$7+6\left(8-\left(-2\right)\right)$$

The opposite of -2 is 2.

$$7+6\left(8+2\right)$$

Add 8 and 2 to get 10.

$$7+6\times 10$$

Multiply 6 and 10 to get 60.

$$7+60$$

Add 7 and 60 to get 67.

$$67$$

Factor

$$67$$