Solve [2-(-3)(-1)^4](-4+3)+[(-6+4):(-2)]^3-sqrt{34^2}

$$[ 2 - ( - 3 ) ( - 1 ) ^ { 4 } ] ( - 4 + 3 ) + [ ( - 6 + 4 ) : ( - 2 ) ] ^ { 3 } - \sqrt { 34 ^ { 2 } }$$

Evaluate

$$-38$$

Solution Steps

Calculate -1 to the power of 4 and get 1.

$$\left(2-\left(-3\right)\right)\left(-4+3\right)+\left(\frac{-6+4}{-2}\right)^{3}-\sqrt{34^{2}}$$

The opposite of -3 is 3.

$$\left(2+3\right)\left(-4+3\right)+\left(\frac{-6+4}{-2}\right)^{3}-\sqrt{34^{2}}$$

Add 2 and 3 to get 5.

$$5\left(-4+3\right)+\left(\frac{-6+4}{-2}\right)^{3}-\sqrt{34^{2}}$$

Add -4 and 3 to get -1.

$$5\left(-1\right)+\left(\frac{-6+4}{-2}\right)^{3}-\sqrt{34^{2}}$$

Multiply 5 and -1 to get -5.

$$-5+\left(\frac{-6+4}{-2}\right)^{3}-\sqrt{34^{2}}$$

Add -6 and 4 to get -2.

$$-5+\left(\frac{-2}{-2}\right)^{3}-\sqrt{34^{2}}$$

Divide -2 by -2 to get 1.

$$-5+1^{3}-\sqrt{34^{2}}$$

Calculate 1 to the power of 3 and get 1.

$$-5+1-\sqrt{34^{2}}$$

Add -5 and 1 to get -4.

$$-4-\sqrt{34^{2}}$$

Calculate 34 to the power of 2 and get 1156.

$$-4-\sqrt{1156}$$

Calculate the square root of 1156 and get 34.

$$-4-34$$

Subtract 34 from -4 to get -38.

$$-38$$

Factor

$$-38$$