Solve [2*(4-12:(-3))+3]:(10-3*(-3))

$$[ 2 \cdot ( 4 - 12 : ( - 3 ) ) + 3 ] : ( 10 - 3 \cdot ( - 3 ) )$$

Evaluate

$$1$$

Solution Steps

Divide 12 by -3 to get -4.

$$\frac{2\left(4-\left(-4\right)\right)+3}{10-3\left(-3\right)}$$

The opposite of -4 is 4.

$$\frac{2\left(4+4\right)+3}{10-3\left(-3\right)}$$

Add 4 and 4 to get 8.

$$\frac{2\times 8+3}{10-3\left(-3\right)}$$

Multiply 2 and 8 to get 16.

$$\frac{16+3}{10-3\left(-3\right)}$$

Add 16 and 3 to get 19.

$$\frac{19}{10-3\left(-3\right)}$$

Multiply 3 and -3 to get -9.

$$\frac{19}{10-\left(-9\right)}$$

The opposite of -9 is 9.

$$\frac{19}{10+9}$$

Add 10 and 9 to get 19.

$$\frac{19}{19}$$

Divide 19 by 19 to get 1.

$$1$$

Factor

$$1$$