Solve [2^2-3(2-3)^3]^3

$$[ 2 ^ { 2 } - 3 ( 2 - 3 ) ^ { 3 } ] ^ { 3 }$$

Evaluate

$$343$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\left(4-3\left(2-3\right)^{3}\right)^{3}$$

Subtract 3 from 2 to get -1.

$$\left(4-3\left(-1\right)^{3}\right)^{3}$$

Calculate -1 to the power of 3 and get -1.

$$\left(4-3\left(-1\right)\right)^{3}$$

Multiply 3 and -1 to get -3.

$$\left(4-\left(-3\right)\right)^{3}$$

The opposite of -3 is 3.

$$\left(4+3\right)^{3}$$

Add 4 and 3 to get 7.

$$7^{3}$$

Calculate 7 to the power of 3 and get 343.

$$343$$

Factor

$$7^{3}$$