Solve [2^{0}+(-3)]^{2}*(-4+6)^5*(8-10)^6-2^10*(-1+3)^3

$$[ 2 ^ { 0 } + ( - 3 ) ] ^ { 2 } \cdot ( - 4 + 6 ) ^ { 5 } \cdot ( 8 - 10 ) ^ { 6 } - 2 ^ { 10 } \cdot ( - 1 + 3 ) ^ { 3 }$$

Evaluate

$$0$$

Solution Steps

Calculate 2 to the power of 0 and get 1.

$$\left(1-3\right)^{2}\left(-4+6\right)^{5}\left(8-10\right)^{6}-2^{10}\left(-1+3\right)^{3}$$

Subtract 3 from 1 to get -2.

$$\left(-2\right)^{2}\left(-4+6\right)^{5}\left(8-10\right)^{6}-2^{10}\left(-1+3\right)^{3}$$

Calculate -2 to the power of 2 and get 4.

$$4\left(-4+6\right)^{5}\left(8-10\right)^{6}-2^{10}\left(-1+3\right)^{3}$$

Add -4 and 6 to get 2.

$$4\times 2^{5}\left(8-10\right)^{6}-2^{10}\left(-1+3\right)^{3}$$

Calculate 2 to the power of 5 and get 32.

$$4\times 32\left(8-10\right)^{6}-2^{10}\left(-1+3\right)^{3}$$

Multiply 4 and 32 to get 128.

$$128\left(8-10\right)^{6}-2^{10}\left(-1+3\right)^{3}$$

Subtract 10 from 8 to get -2.

$$128\left(-2\right)^{6}-2^{10}\left(-1+3\right)^{3}$$

Calculate -2 to the power of 6 and get 64.

$$128\times 64-2^{10}\left(-1+3\right)^{3}$$

Multiply 128 and 64 to get 8192.

$$8192-2^{10}\left(-1+3\right)^{3}$$

Calculate 2 to the power of 10 and get 1024.

$$8192-1024\left(-1+3\right)^{3}$$

Add -1 and 3 to get 2.

$$8192-1024\times 2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$8192-1024\times 8$$

Multiply 1024 and 8 to get 8192.

$$8192-8192$$

Subtract 8192 from 8192 to get 0.

$$0$$

Factor

$$0$$