Solve [19:(5+3.8-10)]-(-2)^2

$$[ 19 : ( 5 + 3.8 - 10 ) ] - ( - 2 ) ^ { 2 }$$

Evaluate

$$-\frac{119}{6}\approx -19.833333333$$

Solution Steps

Add 5 and 3.8 to get 8.8.

$$\frac{19}{8.8-10}-\left(-2\right)^{2}$$

Subtract 10 from 8.8 to get -1.2.

$$\frac{19}{-1.2}-\left(-2\right)^{2}$$

Expand \frac{19}{-1.2} by multiplying both numerator and the denominator by 10.

$$\frac{190}{-12}-\left(-2\right)^{2}$$

Reduce the fraction \frac{190}{-12} to lowest terms by extracting and canceling out 2.

$$-\frac{95}{6}-\left(-2\right)^{2}$$

Calculate -2 to the power of 2 and get 4.

$$-\frac{95}{6}-4$$

Convert 4 to fraction \frac{24}{6}.

$$-\frac{95}{6}-\frac{24}{6}$$

Since -\frac{95}{6} and \frac{24}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-95-24}{6}$$

Subtract 24 from -95 to get -119.

$$-\frac{119}{6}$$

Factor

$$-\frac{119}{6} = -19\frac{5}{6} = -19.833333333333332$$