Solve [15-(-34+12)-(-3)]*(12div4)*(12-4)]-(15*8)

$$[ 15 - ( - 34 + 12 ) - ( - 3 ) ] \cdot ( 12 \div 4 ) \cdot ( 12 - 4 ) ] - ( 15 \cdot 8 )$$

Evaluate

$$960$$

Solution Steps

Add -34 and 12 to get -22.

$$\left(15-\left(-22\right)-\left(-3\right)\right)\times \frac{12}{4}\left(12-4\right)$$

The opposite of -22 is 22.

$$\left(15+22-\left(-3\right)\right)\times \frac{12}{4}\left(12-4\right)$$

Add 15 and 22 to get 37.

$$\left(37-\left(-3\right)\right)\times \frac{12}{4}\left(12-4\right)$$

The opposite of -3 is 3.

$$\left(37+3\right)\times \frac{12}{4}\left(12-4\right)$$

Add 37 and 3 to get 40.

$$40\times \frac{12}{4}\left(12-4\right)$$

Divide 12 by 4 to get 3.

$$40\times 3\left(12-4\right)$$

Multiply 40 and 3 to get 120.

$$120\left(12-4\right)$$

Subtract 4 from 12 to get 8.

$$120\times 8$$

Multiply 120 and 8 to get 960.

$$960$$

Factor

$$2^{6}\times 3\times 5$$