Solve [15-(-3)*4]div[-8+2*5-11]div(-2-1)

$$[ 15 - ( - 3 ) \cdot 4 ] \div [ - 8 + 2 \cdot 5 - 11 ] \div ( - 2 - 1 )$$

Evaluate

$$1$$

Solution Steps

Multiply -3 and 4 to get -12.

$$\frac{\frac{15-\left(-12\right)}{-8+2\times 5-11}}{-2-1}$$

The opposite of -12 is 12.

$$\frac{\frac{15+12}{-8+2\times 5-11}}{-2-1}$$

Add 15 and 12 to get 27.

$$\frac{\frac{27}{-8+2\times 5-11}}{-2-1}$$

Multiply 2 and 5 to get 10.

$$\frac{\frac{27}{-8+10-11}}{-2-1}$$

Add -8 and 10 to get 2.

$$\frac{\frac{27}{2-11}}{-2-1}$$

Subtract 11 from 2 to get -9.

$$\frac{\frac{27}{-9}}{-2-1}$$

Divide 27 by -9 to get -3.

$$\frac{-3}{-2-1}$$

Subtract 1 from -2 to get -3.

$$\frac{-3}{-3}$$

Divide -3 by -3 to get 1.

$$1$$

Factor

$$1$$