Solve [12]-7*1+([7*(18-3*6):(9:[5-2])]+1+7*3+7

$$[ 12 ] - 7 \cdot 1 + ( [ 7 \cdot ( 18 - 3 \cdot 6 ) : ( 9 : [ 5 - 2 ] ) ] + 1 + 7 \cdot 3 + 7$$

Evaluate

$$34$$

Solution Steps

Multiply 7 and 1 to get 7.

$$12-7+\frac{7\left(18-3\times 6\right)}{\frac{9}{5-2}}+1+7\times 3+7$$

Subtract 7 from 12 to get 5.

$$5+\frac{7\left(18-3\times 6\right)}{\frac{9}{5-2}}+1+7\times 3+7$$

Multiply 3 and 6 to get 18.

$$5+\frac{7\left(18-18\right)}{\frac{9}{5-2}}+1+7\times 3+7$$

Subtract 18 from 18 to get 0.

$$5+\frac{7\times 0}{\frac{9}{5-2}}+1+7\times 3+7$$

Multiply 7 and 0 to get 0.

$$5+\frac{0}{\frac{9}{5-2}}+1+7\times 3+7$$

Subtract 2 from 5 to get 3.

$$5+\frac{0}{\frac{9}{3}}+1+7\times 3+7$$

Divide 9 by 3 to get 3.

$$5+\frac{0}{3}+1+7\times 3+7$$

Zero divided by any non-zero number gives zero.

$$5+0+1+7\times 3+7$$

Add 5 and 0 to get 5.

$$5+1+7\times 3+7$$

Add 5 and 1 to get 6.

$$6+7\times 3+7$$

Multiply 7 and 3 to get 21.

$$6+21+7$$

Add 6 and 21 to get 27.

$$27+7$$

Add 27 and 7 to get 34.

$$34$$

Factor

$$2\times 17$$