Solve [1-(1-05*1/2)]*[2-(-3)^2]

$$[ 1 - ( 1 - 05 \times \frac { 1 } { 2 } ) ] \times [ 2 - ( - 3 ) ^ { 2 } ]$$

Evaluate

$$0$$

Solution Steps

Multiply 0 and 5 to get 0.

$$\left(1-\left(1-0\times \frac{1}{2}\right)\right)\left(2-\left(-3\right)^{2}\right)$$

Multiply 0 and \frac{1}{2} to get 0.

$$\left(1-\left(1-0\right)\right)\left(2-\left(-3\right)^{2}\right)$$

Subtract 0 from 1 to get 1.

$$\left(1-1\right)\left(2-\left(-3\right)^{2}\right)$$

Subtract 1 from 1 to get 0.

$$0\left(2-\left(-3\right)^{2}\right)$$

Calculate -3 to the power of 2 and get 9.

$$0\left(2-9\right)$$

Subtract 9 from 2 to get -7.

$$0\left(-7\right)$$

Multiply 0 and -7 to get 0.

$$0$$

Factor

$$0$$