Solve [1-(1-0.5*1/2)]*[2-(-3)^2]

$$[ 1 - ( 1 - 0.5 \times \frac { 1 } { 2 } ) ] \times [ 2 - ( - 3 ) ^ { 2 } ]$$

Evaluate

$$-1.75$$

Solution Steps

Convert decimal number 0.5 to fraction \frac{5}{10}. Reduce the fraction \frac{5}{10} to lowest terms by extracting and canceling out 5.

$$\left(1-\left(1-\frac{1}{2}\times \frac{1}{2}\right)\right)\left(2-\left(-3\right)^{2}\right)$$

Multiply \frac{1}{2} times \frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$\left(1-\left(1-\frac{1\times 1}{2\times 2}\right)\right)\left(2-\left(-3\right)^{2}\right)$$

Do the multiplications in the fraction \frac{1\times 1}{2\times 2}.

$$\left(1-\left(1-\frac{1}{4}\right)\right)\left(2-\left(-3\right)^{2}\right)$$

Convert 1 to fraction \frac{4}{4}.

$$\left(1-\left(\frac{4}{4}-\frac{1}{4}\right)\right)\left(2-\left(-3\right)^{2}\right)$$

Since \frac{4}{4} and \frac{1}{4} have the same denominator, subtract them by subtracting their numerators.

$$\left(1-\frac{4-1}{4}\right)\left(2-\left(-3\right)^{2}\right)$$

Subtract 1 from 4 to get 3.

$$\left(1-\frac{3}{4}\right)\left(2-\left(-3\right)^{2}\right)$$

Convert 1 to fraction \frac{4}{4}.

$$\left(\frac{4}{4}-\frac{3}{4}\right)\left(2-\left(-3\right)^{2}\right)$$

Since \frac{4}{4} and \frac{3}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4-3}{4}\left(2-\left(-3\right)^{2}\right)$$

Subtract 3 from 4 to get 1.

$$\frac{1}{4}\left(2-\left(-3\right)^{2}\right)$$

Calculate -3 to the power of 2 and get 9.

$$\frac{1}{4}\left(2-9\right)$$

Subtract 9 from 2 to get -7.

$$\frac{1}{4}\left(-7\right)$$

Multiply \frac{1}{4} and -7 to get \frac{-7}{4}.

$$\frac{-7}{4}$$

Fraction \frac{-7}{4} can be rewritten as -\frac{7}{4} by extracting the negative sign.

$$-\frac{7}{4}$$

Factor

$$-1.75$$