Solve [1-(1/20+1/30)*3]1/1=

$$[ 1 - ( \frac { 1 } { 20 } + \frac { 1 } { 30 } ) \times 3 ] \frac { 1 } { 1 } =$$

Evaluate

$$\frac{3}{4}=0.75$$

Solution Steps

Divide 1 by 1 to get 1.

$$\left(1-\left(\frac{1}{20}+\frac{1}{30}\right)\times 3\right)\times 1$$

Least common multiple of 20 and 30 is 60. Convert \frac{1}{20} and \frac{1}{30} to fractions with denominator 60.

$$\left(1-\left(\frac{3}{60}+\frac{2}{60}\right)\times 3\right)\times 1$$

Since \frac{3}{60} and \frac{2}{60} have the same denominator, add them by adding their numerators.

$$\left(1-\frac{3+2}{60}\times 3\right)\times 1$$

Add 3 and 2 to get 5.

$$\left(1-\frac{5}{60}\times 3\right)\times 1$$

Reduce the fraction \frac{5}{60} to lowest terms by extracting and canceling out 5.

$$\left(1-\frac{1}{12}\times 3\right)\times 1$$

Multiply \frac{1}{12} and 3 to get \frac{3}{12}.

$$\left(1-\frac{3}{12}\right)\times 1$$

Reduce the fraction \frac{3}{12} to lowest terms by extracting and canceling out 3.

$$\left(1-\frac{1}{4}\right)\times 1$$

Convert 1 to fraction \frac{4}{4}.

$$\left(\frac{4}{4}-\frac{1}{4}\right)\times 1$$

Since \frac{4}{4} and \frac{1}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4-1}{4}\times 1$$

Subtract 1 from 4 to get 3.

$$\frac{3}{4}\times 1$$

Multiply \frac{3}{4} and 1 to get \frac{3}{4}.

$$\frac{3}{4}$$

Factor

$$\frac{3}{2 ^ {2}} = 0.75$$