Solve [1-3/4*1/9+1/5-(1/2+1)^2+2*(frac{2}{3}-frac{1}{4})]+1=

$$[ 1 - \frac { 3 } { 4 } \cdot \frac { 1 } { 9 } + \frac { 1 } { 5 } - ( \frac { 1 } { 2 } + 1 ) ^ { 2 } + 2 \cdot ( \frac { 2 } { 3 } - \frac { 1 } { 4 } ) ] + 1 =$$

Evaluate

$$\frac{7}{10}=0.7$$

Solution Steps

Multiply \frac{3}{4} and \frac{1}{9} to get \frac{1}{12}.

$$1-\frac{1}{12}+\frac{1}{5}-\left(\frac{1}{2}+1\right)^{2}+2\left(\frac{2}{3}-\frac{1}{4}\right)+1$$

Subtract \frac{1}{12} from 1 to get \frac{11}{12}.

$$\frac{11}{12}+\frac{1}{5}-\left(\frac{1}{2}+1\right)^{2}+2\left(\frac{2}{3}-\frac{1}{4}\right)+1$$

Add \frac{11}{12} and \frac{1}{5} to get \frac{67}{60}.

$$\frac{67}{60}-\left(\frac{1}{2}+1\right)^{2}+2\left(\frac{2}{3}-\frac{1}{4}\right)+1$$

Add \frac{1}{2} and 1 to get \frac{3}{2}.

$$\frac{67}{60}-\left(\frac{3}{2}\right)^{2}+2\left(\frac{2}{3}-\frac{1}{4}\right)+1$$

Calculate \frac{3}{2} to the power of 2 and get \frac{9}{4}.

$$\frac{67}{60}-\frac{9}{4}+2\left(\frac{2}{3}-\frac{1}{4}\right)+1$$

Subtract \frac{9}{4} from \frac{67}{60} to get -\frac{17}{15}.

$$-\frac{17}{15}+2\left(\frac{2}{3}-\frac{1}{4}\right)+1$$

Subtract \frac{1}{4} from \frac{2}{3} to get \frac{5}{12}.

$$-\frac{17}{15}+2\times \frac{5}{12}+1$$

Multiply 2 and \frac{5}{12} to get \frac{5}{6}.

$$-\frac{17}{15}+\frac{5}{6}+1$$

Add -\frac{17}{15} and \frac{5}{6} to get -\frac{3}{10}.

$$-\frac{3}{10}+1$$

Add -\frac{3}{10} and 1 to get \frac{7}{10}.

$$\frac{7}{10}$$

Factor

$$\frac{7}{2 \cdot 5} = 0.7$$