Solve [13/4-1/8]33quad21/5

$$[ 1 \frac { 3 } { 4 } - \frac { 1 } { 8 } ] 33 \quad 2 \frac { 1 } { 5 }$$

Evaluate

$$\frac{4719}{40}=117.975$$

Solution Steps

Multiply 1 and 4 to get 4.

$$\left(\frac{4+3}{4}-\frac{1}{8}\right)\times 33\times \frac{2\times 5+1}{5}$$

Add 4 and 3 to get 7.

$$\left(\frac{7}{4}-\frac{1}{8}\right)\times 33\times \frac{2\times 5+1}{5}$$

Least common multiple of 4 and 8 is 8. Convert \frac{7}{4} and \frac{1}{8} to fractions with denominator 8.

$$\left(\frac{14}{8}-\frac{1}{8}\right)\times 33\times \frac{2\times 5+1}{5}$$

Since \frac{14}{8} and \frac{1}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{14-1}{8}\times 33\times \frac{2\times 5+1}{5}$$

Subtract 1 from 14 to get 13.

$$\frac{13}{8}\times 33\times \frac{2\times 5+1}{5}$$

Express \frac{13}{8}\times 33 as a single fraction.

$$\frac{13\times 33}{8}\times \frac{2\times 5+1}{5}$$

Multiply 13 and 33 to get 429.

$$\frac{429}{8}\times \frac{2\times 5+1}{5}$$

Multiply 2 and 5 to get 10.

$$\frac{429}{8}\times \frac{10+1}{5}$$

Add 10 and 1 to get 11.

$$\frac{429}{8}\times \frac{11}{5}$$

Multiply \frac{429}{8} times \frac{11}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{429\times 11}{8\times 5}$$

Do the multiplications in the fraction \frac{429\times 11}{8\times 5}.

$$\frac{4719}{40}$$

Factor

$$\frac{3 \cdot 11 ^ {2} \cdot 13}{2 ^ {3} \cdot 5} = 117\frac{39}{40} = 117.975$$