Solve [0,6*(2-4/5)-(1-2/5-0,25)*-4]:1,8=

$$[ 0,6 \cdot ( 2 - \frac { 4 } { 5 } ) - ( 1 - \frac { 2 } { 5 } - 0,25 ) \cdot - 4 ] : 1,8 =$$

Evaluate

$$\frac{53}{45}\approx 1,177777778$$

Solution Steps

Convert 2 to fraction \frac{10}{5}.

$$\frac{0,6\left(\frac{10}{5}-\frac{4}{5}\right)-\left(1-\frac{2}{5}-0,25\right)\left(-4\right)}{1,8}$$

Since \frac{10}{5} and \frac{4}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{0,6\times \frac{10-4}{5}-\left(1-\frac{2}{5}-0,25\right)\left(-4\right)}{1,8}$$

Subtract 4 from 10 to get 6.

$$\frac{0,6\times \frac{6}{5}-\left(1-\frac{2}{5}-0,25\right)\left(-4\right)}{1,8}$$

Convert decimal number 0,6 to fraction \frac{6}{10}. Reduce the fraction \frac{6}{10} to lowest terms by extracting and canceling out 2.

$$\frac{\frac{3}{5}\times \frac{6}{5}-\left(1-\frac{2}{5}-0,25\right)\left(-4\right)}{1,8}$$

Multiply \frac{3}{5} times \frac{6}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\frac{3\times 6}{5\times 5}-\left(1-\frac{2}{5}-0,25\right)\left(-4\right)}{1,8}$$

Do the multiplications in the fraction \frac{3\times 6}{5\times 5}.

$$\frac{\frac{18}{25}-\left(1-\frac{2}{5}-0,25\right)\left(-4\right)}{1,8}$$

Convert 1 to fraction \frac{5}{5}.

$$\frac{\frac{18}{25}-\left(\frac{5}{5}-\frac{2}{5}-0,25\right)\left(-4\right)}{1,8}$$

Since \frac{5}{5} and \frac{2}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{18}{25}-\left(\frac{5-2}{5}-0,25\right)\left(-4\right)}{1,8}$$

Subtract 2 from 5 to get 3.

$$\frac{\frac{18}{25}-\left(\frac{3}{5}-0,25\right)\left(-4\right)}{1,8}$$

Convert decimal number 0,25 to fraction \frac{25}{100}. Reduce the fraction \frac{25}{100} to lowest terms by extracting and canceling out 25.

$$\frac{\frac{18}{25}-\left(\frac{3}{5}-\frac{1}{4}\right)\left(-4\right)}{1,8}$$

Least common multiple of 5 and 4 is 20. Convert \frac{3}{5} and \frac{1}{4} to fractions with denominator 20.

$$\frac{\frac{18}{25}-\left(\frac{12}{20}-\frac{5}{20}\right)\left(-4\right)}{1,8}$$

Since \frac{12}{20} and \frac{5}{20} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{18}{25}-\frac{12-5}{20}\left(-4\right)}{1,8}$$

Subtract 5 from 12 to get 7.

$$\frac{\frac{18}{25}-\frac{7}{20}\left(-4\right)}{1,8}$$

Express \frac{7}{20}\left(-4\right) as a single fraction.

$$\frac{\frac{18}{25}-\frac{7\left(-4\right)}{20}}{1,8}$$

Multiply 7 and -4 to get -28.

$$\frac{\frac{18}{25}-\frac{-28}{20}}{1,8}$$

Reduce the fraction \frac{-28}{20} to lowest terms by extracting and canceling out 4.

$$\frac{\frac{18}{25}-\left(-\frac{7}{5}\right)}{1,8}$$

The opposite of -\frac{7}{5} is \frac{7}{5}.

$$\frac{\frac{18}{25}+\frac{7}{5}}{1,8}$$

Least common multiple of 25 and 5 is 25. Convert \frac{18}{25} and \frac{7}{5} to fractions with denominator 25.

$$\frac{\frac{18}{25}+\frac{35}{25}}{1,8}$$

Since \frac{18}{25} and \frac{35}{25} have the same denominator, add them by adding their numerators.

$$\frac{\frac{18+35}{25}}{1,8}$$

Add 18 and 35 to get 53.

$$\frac{\frac{53}{25}}{1,8}$$

Express \frac{\frac{53}{25}}{1,8} as a single fraction.

$$\frac{53}{25\times 1,8}$$

Multiply 25 and 1,8 to get 45.

$$\frac{53}{45}$$

Factor

$$\frac{53}{5 \cdot 3 ^ {2}} = 1\frac{8}{45} = 1.1777777777777778$$