Solve [0-1/2(1)^2]+[1/22^2-0]=

$$[ 0 - \frac { 1 } { 2 } ( 1 ) ^ { 2 } ] + [ \frac { 1 } { 2 } 2 ^ { 2 } - 0 ] =$$

Evaluate

$$\frac{3}{2}=1.5$$

Solution Steps

Calculate 1 to the power of 2 and get 1.

$$0-\frac{1}{2}\times 1+\frac{1}{2}\times 2^{2}-0$$

Multiply \frac{1}{2} and 1 to get \frac{1}{2}.

$$0-\frac{1}{2}+\frac{1}{2}\times 2^{2}-0$$

Subtract \frac{1}{2} from 0 to get -\frac{1}{2}.

$$-\frac{1}{2}+\frac{1}{2}\times 2^{2}-0$$

Calculate 2 to the power of 2 and get 4.

$$-\frac{1}{2}+\frac{1}{2}\times 4-0$$

Multiply \frac{1}{2} and 4 to get \frac{4}{2}.

$$-\frac{1}{2}+\frac{4}{2}-0$$

Divide 4 by 2 to get 2.

$$-\frac{1}{2}+2-0$$

Subtract 0 from 2 to get 2.

$$-\frac{1}{2}+2$$

Convert 2 to fraction \frac{4}{2}.

$$-\frac{1}{2}+\frac{4}{2}$$

Since -\frac{1}{2} and \frac{4}{2} have the same denominator, add them by adding their numerators.

$$\frac{-1+4}{2}$$

Add -1 and 4 to get 3.

$$\frac{3}{2}$$

Factor

$$\frac{3}{2} = 1\frac{1}{2} = 1.5$$