Solve [0^{5}+1^{7}+(-1)^17-(-3)^27:(-3)^26]*2^2+|-4|

$$[ 0 ^ { 5 } + 1 ^ { 7 } + ( - 1 ) ^ { 17 } - ( - 3 ) ^ { 27 } : ( - 3 ) ^ { 26 } ] \cdot 2 ^ { 2 } + | - 4 |$$

Evaluate

$$16$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 26 from 27 to get 1.

$$\left(0^{5}+1^{7}+\left(-1\right)^{17}-\left(-3\right)^{1}\right)\times 2^{2}+|-4|$$

Calculate 0 to the power of 5 and get 0.

$$\left(0+1^{7}+\left(-1\right)^{17}-\left(-3\right)^{1}\right)\times 2^{2}+|-4|$$

Calculate 1 to the power of 7 and get 1.

$$\left(0+1+\left(-1\right)^{17}-\left(-3\right)^{1}\right)\times 2^{2}+|-4|$$

Add 0 and 1 to get 1.

$$\left(1+\left(-1\right)^{17}-\left(-3\right)^{1}\right)\times 2^{2}+|-4|$$

Calculate -1 to the power of 17 and get -1.

$$\left(1-1-\left(-3\right)^{1}\right)\times 2^{2}+|-4|$$

Subtract 1 from 1 to get 0.

$$\left(-\left(-3\right)^{1}\right)\times 2^{2}+|-4|$$

Calculate -3 to the power of 1 and get -3.

$$\left(-\left(-3\right)\right)\times 2^{2}+|-4|$$

The opposite of -3 is 3.

$$3\times 2^{2}+|-4|$$

Calculate 2 to the power of 2 and get 4.

$$3\times 4+|-4|$$

Multiply 3 and 4 to get 12.

$$12+|-4|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -4 is 4.

$$12+4$$

Add 12 and 4 to get 16.

$$16$$

Factor

$$2^{4}$$