Solve [-625:(-5)^4+32:(-2)^5+4*(-29+11)]:(-37)=

$$[ - 625 : ( - 5 ) ^ { 4 } + 32 : ( - 2 ) ^ { 5 } + 4 \cdot ( - 29 + 11 ) ] : ( - 37 ) =$$

Evaluate

$$2$$

Solution Steps

Calculate -5 to the power of 4 and get 625.

$$\frac{\frac{-625}{625}+\frac{32}{\left(-2\right)^{5}}+4\left(-29+11\right)}{-37}$$

Divide -625 by 625 to get -1.

$$\frac{-1+\frac{32}{\left(-2\right)^{5}}+4\left(-29+11\right)}{-37}$$

Calculate -2 to the power of 5 and get -32.

$$\frac{-1+\frac{32}{-32}+4\left(-29+11\right)}{-37}$$

Divide 32 by -32 to get -1.

$$\frac{-1-1+4\left(-29+11\right)}{-37}$$

Subtract 1 from -1 to get -2.

$$\frac{-2+4\left(-29+11\right)}{-37}$$

Add -29 and 11 to get -18.

$$\frac{-2+4\left(-18\right)}{-37}$$

Multiply 4 and -18 to get -72.

$$\frac{-2-72}{-37}$$

Subtract 72 from -2 to get -74.

$$\frac{-74}{-37}$$

Divide -74 by -37 to get 2.

$$2$$

Factor

$$2$$