Solve [-5+2^2*3-3*(-4)]-3^2*sqrt{16}+sqrt{75+6}

$$[ - 5 + 2 ^ { 2 } \cdot 3 - 3 \cdot ( - 4 ) ] - 3 ^ { 2 } \cdot \sqrt { 16 } + \sqrt { 75 + 6 }$$

Evaluate

$$-8$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$-5+4\times 3-3\left(-4\right)-3^{2}\sqrt{16}+\sqrt{75+6}$$

Multiply 4 and 3 to get 12.

$$-5+12-3\left(-4\right)-3^{2}\sqrt{16}+\sqrt{75+6}$$

Add -5 and 12 to get 7.

$$7-3\left(-4\right)-3^{2}\sqrt{16}+\sqrt{75+6}$$

Multiply 3 and -4 to get -12.

$$7-\left(-12\right)-3^{2}\sqrt{16}+\sqrt{75+6}$$

The opposite of -12 is 12.

$$7+12-3^{2}\sqrt{16}+\sqrt{75+6}$$

Add 7 and 12 to get 19.

$$19-3^{2}\sqrt{16}+\sqrt{75+6}$$

Calculate 3 to the power of 2 and get 9.

$$19-9\sqrt{16}+\sqrt{75+6}$$

Calculate the square root of 16 and get 4.

$$19-9\times 4+\sqrt{75+6}$$

Multiply 9 and 4 to get 36.

$$19-36+\sqrt{75+6}$$

Subtract 36 from 19 to get -17.

$$-17+\sqrt{75+6}$$

Add 75 and 6 to get 81.

$$-17+\sqrt{81}$$

Calculate the square root of 81 and get 9.

$$-17+9$$

Add -17 and 9 to get -8.

$$-8$$

Factor

$$-8$$